8b^2+256=-96b

Solution for 8b^2+256=-96b equation:

8b^2+256=-96b

We move all terms to the left:

8b^2+256-(-96b)=0

We get rid of parentheses

8b^2+96b+256=0

a = 8; b = 96; c = +256;
Δ = b2-4ac
Δ = 962-4·8·256
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-32}{2*8}=\frac{-128}{16}
=-8
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+32}{2*8}=\frac{-64}{16}
=-4
$